A charge of 10^{-3} mu C is placed at the or | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electric potential $V$ at a distance $r$ from a point charge $q$ is given by $V = \frac{kq}{r}$.For point $A$ at $(\sqrt{2}, \sqrt{2})$,the di

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) The electric potential $V$ at a distance $r$ from a point charge $q$ is given by $V = \frac{kq}{r}$.For point $A$ at $(\sqrt{2}, \sqrt{2})$,the distance from the origin $(0, 0)$ is $r_A = \sqrt{(\sqrt{2})^2 + (\sqrt{2})^2} = \sqrt{2 + 2} = \sqrt{4} = 2$.For point $B$ at $(2, 0)$,the distance from the origin $(0, 0)$ is $r_B = \sqrt{2^2 + 0^2} = 2$.Since the distances $r_A$ and $r_B$ are equal,the electric potentials at points $A$ and $B$ are equal:$V_A = \frac{kq}{r_A} = \frac{kq}{2}$$V_B = \frac{kq}{r_B} = \frac{kq}{2}$Therefore,the potential difference between points $A$ and $B$ is:$V_A - V_B = \frac{kq}{2} - \frac{kq}{2} = 0 \ V$.

$A$ charge of $10^{-3} \ \mu C$ is placed at the origin $(0, 0)$ of an $X-Y$ coordinate system. Two points $A$ and $B$ are located at $(\sqrt{2}, \sqrt{2})$ and $(2, 0)$ respectively. The potential difference between points $A$ and $B$ is ....... $V$.

Similar Questions

$A$ hollow charged metal sphere has radius $R$. If the potential difference between its surface and a point at a distance $5R$ from the centre is $V$,then the magnitude of the electric field intensity at a distance $5R$ from the centre of the sphere is:

Write expressions for electric potential due to a continuous distribution of charges.

Two point charges $-20 \,\mu C$ and $+40 \,\mu C$ are separated by a distance $r$. At which region$(s)$ will the electric potential be zero?

$A$ charged spherical conductor has radius '$r$'. The potential difference between its surface and a point at a distance '$3r$' from the center is '$V$'. The electric intensity at a distance '$3r$' from the center of the conductor is:

If four charges $+12 \text{ nC}, -20 \text{ nC}, +32 \text{ nC}$ and $-15 \text{ nC}$ are arranged at the four vertices of a square of side $\sqrt{2} \text{ m}$,then the net electric potential at the centre of the square due to these four charges is (in $\text{ V}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module