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(C) The capacitance $C$ of a parallel plate capacitor is given by the formula $C = \frac{\epsilon_0 A}{d}$.Here,the area $A = 5 \, km 	imes 5 \, km =

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$0.22$

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(C) The capacitance $C$ of a parallel plate capacitor is given by the formula $C = \frac{\epsilon_0 A}{d}$.Here,the area $A = 5 \, km 	imes 5 \, km = (5 	imes 10^3 \, m) 	imes (5 	imes 10^3 \, m) = 25 	imes 10^6 \, m^2$.The distance $d = 1 \, km = 10^3 \, m$.The permittivity of free space $\epsilon_0 = 8.854 	imes 10^{-12} \, F/m$.Substituting these values into the formula:$C = \frac{8.854 	imes 10^{-12} 	imes 25 	imes 10^6}{10^3}$$C = 8.854 	imes 25 	imes 10^{-12+6-3}$$C = 221.35 	imes 10^{-9} \, F$$C = 0.22135 	imes 10^{-6} \, F = 0.22 \, \mu F$.

$A$ large cloud of size $5 \, km \times 5 \, km$ is hovering over the Earth at a height of $1 \, km$. Assuming the cloud and the Earth form a parallel plate capacitor with air as the dielectric,calculate the capacitance of the cloud-Earth system in $\mu F$.

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