In the symbol of a transistor,the arrow indicates the direction of:

$A$ change of $0.04 \ V$ takes place between the base and the emitter when an input signal is connected to the common emitter transistor amplifier. As a result,a $20 \ \mu A$ change takes place in the base current and a change of $2 \ mA$ takes place in the collector current. The input resistance and $AC$ current gain are:

An $n-p-n$ transistor can be considered to be equivalent to two diodes connected back-to-back. Which of the following figures correctly represents this equivalent circuit?

In common emitter mode of a transistor, the d.c. current gain $(\beta)$ is $20$, and the emitter current $(I_E)$ is $7 \text{ mA}$. The collector current $(I_C)$ is:

In the figure,given that $V_{BB}$ supply can vary from $0$ to $5.0 \,V$,$V_{CC} = 5\,V$,$\beta_{dc} = 200$,$R_B = 100\,k\Omega$,$R_C = 1\,k\Omega$ and $V_{BE} = 1.0\,V$. The minimum base current and the input voltage at which the transistor will go to saturation,will be respectively:

An $npn$ transistor operates as a common emitter amplifier,with a power gain of $60\, dB$. The input circuit resistance is $100\,\Omega$ and the output load resistance is $10\, k\Omega$. The common emitter current gain $\beta$ is: