In common emitter mode of a transistor, the d | vedclass

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(A) Given:$d.c. 	ext{ current gain } (\beta) = 20$$Emitter current (I_E) = 7 	ext{ mA}$We know the relationship between current gain $(\beta)$ and c

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$20/3 	ext{ mA}$

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(A) Given:$d.c. 	ext{ current gain } (\beta) = 20$$Emitter current (I_E) = 7 	ext{ mA}$We know the relationship between current gain $(\beta)$ and collector current $(I_C)$ is given by $I_C = \beta I_B$, where $I_B$ is the base current.Also, $I_E = I_B + I_C$.Substituting $I_B = I_C / \beta$ into the equation:$I_E = I_C / \beta + I_C$$I_E = I_C (1/\beta + 1)$$I_E = I_C (1 + \beta) / \beta$Rearranging to solve for $I_C$:$I_C = I_E 	imes \beta / (1 + \beta)$$I_C = 7 	imes 20 / (1 + 20)$$I_C = 140 / 21$Dividing both numerator and denominator by $7$:$I_C = 20 / 3 	ext{ mA}$.

In common emitter mode of a transistor, the d.c. current gain $(\beta)$ is $20$, and the emitter current $(I_E)$ is $7 \text{ mA}$. The collector current $(I_C)$ is:

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