If alpha is the current gain in a CB circuit | vedclass

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Question

(A) The current gain in a common-base $(CB)$ configuration is defined as $\alpha = \frac{\Delta I_C}{\Delta I_E}$.The current gain in a common-emitter

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$\frac{\Delta I_B}{\Delta I_E}$

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(A) The current gain in a common-base $(CB)$ configuration is defined as $\alpha = \frac{\Delta I_C}{\Delta I_E}$.The current gain in a common-emitter $(CE)$ configuration is defined as $\beta = \frac{\Delta I_C}{\Delta I_B}$.Taking the ratio of $\alpha$ to $\beta$:$\frac{\alpha}{\beta} = \frac{(\Delta I_C / \Delta I_E)}{(\Delta I_C / \Delta I_B)}$$\frac{\alpha}{\beta} = \frac{\Delta I_C}{\Delta I_E} 	imes \frac{\Delta I_B}{\Delta I_C}$$\frac{\alpha}{\beta} = \frac{\Delta I_B}{\Delta I_E}$

If $\alpha$ is the current gain in a $CB$ circuit and $\beta$ is the current gain in a $CE$ circuit,then $\alpha / \beta$ = ......

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