Which logic gate is represented by the follow | vedclass

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(D) The truth table provided is:$A=1, B=1 \implies Y=0$$A=0, B=1 \implies Y=1$$A=1, B=0 \implies Y=1$$A=0, B=0 \implies Y=1$Analyzing the output $Y$,w

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$NAND$ gate

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(D) The truth table provided is:$A=1, B=1 \implies Y=0$$A=0, B=1 \implies Y=1$$A=1, B=0 \implies Y=1$$A=0, B=0 \implies Y=1$Analyzing the output $Y$,we see that the output is $0$ only when both inputs $A$ and $B$ are $1$. In all other cases,the output is $1$.This is the characteristic behavior of a $NAND$ gate,where $Y = \overline{A \cdot B}$.Therefore,the correct option is $D$.

Which logic gate is represented by the following truth table?

$A$ $B$ $Y$

$1$ $1$ $0$

$0$ $1$ $1$

$1$ $0$ $1$

$0$ $0$ $1$

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Which logic gate is represented by the following truth table? $A$ $B$ $Y$ $1$ $1$ $0$ $0$ $1$ $1$ $1$ $0$ $1$ $0$ $0$ $1$