What is the voltage gain of a common-emitter amplifier with an input resistance of $3 \ \Omega$ and a load resistance of $24 \ \Omega$? (Given $\beta = 6$)

In the given circuit,a transistor with a current gain $\beta = 100$ is used. To have $V_{CE} = 5 \text{ V}$ and $V_{BE} = 0$,what should be the value of the base resistance $R_b$?

In a transistor, if $\frac{I_C}{I_E} = \alpha$ and $\frac{I_C}{I_B} = \beta$. If $\alpha$ varies between $\frac{20}{21}$ and $\frac{100}{101}$, then the value of $\beta$ lies between:

The region in the output voltage versus input voltage graph where a transistor can be used as an amplifier is

The voltage gain and current gain of a transistor amplifier in common emitter configuration are respectively $150$ and $50$. If the resistance in the base circuit is $850 \Omega$, then the resistance in the collector circuit is: (in $\Omega$)

Consider an amplifier circuit wherein a transistor is used in common emitter mode. The change in collector current and base current respectively are $4 mA$ and $20 \mu A$ when a signal of $40 mV$ is added to the base-emitter voltage. If the load resistance is $10 k\Omega$, then the power gain in the circuit is: