For the given circuit,find V_{AB} = ......V. | vedclass

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(A) The diode is in forward bias because the potential at point $A$ is higher than the potential at point $B$.The diode and the $10R$ resistor in para

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$10$

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(A) The diode is in forward bias because the potential at point $A$ is higher than the potential at point $B$.The diode and the $10R$ resistor in parallel with the lower $10R$ resistor form an equivalent resistance of $R_{eq} = \frac{10R 	imes 10R}{10R + 10R} = 5R$.Now,the circuit acts as a voltage divider with a $10R$ resistor in series with the equivalent $5R$ resistance.The voltage $V_{AB}$ across the parallel combination is given by the voltage divider rule:$V_{AB} = \left( \frac{5R}{10R + 5R} ight) 	imes 30V$$V_{AB} = \left( \frac{5R}{15R} ight) 	imes 30V$$V_{AB} = \frac{1}{3} 	imes 30V = 10V$.

For the given circuit,find $V_{AB} = ......V$.

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