Which logic gate is represented by the follow | vedclass

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(C) The given truth table is:$A=0, B=0 \implies Y=1$$A=0, B=1 \implies Y=0$$A=1, B=0 \implies Y=0$$A=1, B=1 \implies Y=1$This truth table corresponds

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$XNOR$ gate

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(C) The given truth table is:$A=0, B=0 \implies Y=1$$A=0, B=1 \implies Y=0$$A=1, B=0 \implies Y=0$$A=1, B=1 \implies Y=1$This truth table corresponds to the $XNOR$ gate (Exclusive $NOR$ gate).The Boolean expression for an $XNOR$ gate is $Y = A \odot B = \overline{A \oplus B} = AB + \overline{A}\overline{B}$.Checking the values:For $(0,0): Y = (0)(0) + (1)(1) = 0 + 1 = 1$.For $(0,1): Y = (0)(1) + (1)(0) = 0 + 0 = 0$.For $(1,0): Y = (1)(0) + (0)(1) = 0 + 0 = 0$.For $(1,1): Y = (1)(1) + (0)(0) = 1 + 0 = 1$.Thus,the correct option is $C$.

$A$	$B$	$Y$
$0$	$0$	$1$
$0$	$1$	$0$
$1$	$0$	$0$
$1$	$1$	$1$

Which logic gate is represented by the following truth table?

$A$ $B$ $Y$

$0$ $0$ $1$

$0$ $1$ $0$

$1$ $0$ $0$

$1$ $1$ $1$

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Which logic gate is represented by the following truth table? $A$ $B$ $Y$ $0$ $0$ $1$ $0$ $1$ $0$ $1$ $0$ $0$ $1$ $1$ $1$