A magnifying lens has a focal length of 10 , | vedclass

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(D) For a magnifying lens (convex lens used as a simple magnifier),the object is placed between the optical center and the focus. The image formed is

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$4$

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(D) For a magnifying lens (convex lens used as a simple magnifier),the object is placed between the optical center and the focus. The image formed is virtual,erect,and magnified.Given: Focal length $f = +10 \, cm$,Image distance $v = -30 \, cm$ (since the image is virtual and on the same side as the object).Using the lens formula: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$Substituting the values: $\frac{1}{-30} - \frac{1}{u} = \frac{1}{10}$$-\frac{1}{u} = \frac{1}{10} + \frac{1}{30} = \frac{3+1}{30} = \frac{4}{30}$$u = -\frac{30}{4} = -7.5 \, cm$The magnification $m$ is given by: $m = \frac{v}{u}$$m = \frac{-30}{-7.5} = 4$Thus,the magnification is $4$.

$A$ magnifying lens has a focal length of $10 \, cm$. If the image is formed at a distance of $30 \, cm$ from the lens,what is the magnification?

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