White light is passed through a prism of angl | vedclass

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Question

(A) For a thin prism,the angle of deviation $\delta$ is given by $\delta = (\mu - 1)A$. The deviation for blue light is $\delta_B = (\mu_B - 1)A = (1.

Vedclass · Accepted Answer

$0.090$

Vedclass · Answer

(A) For a thin prism,the angle of deviation $\delta$ is given by $\delta = (\mu - 1)A$. The deviation for blue light is $\delta_B = (\mu_B - 1)A = (1.659 - 1) 	imes 5^{\circ} = 0.659 	imes 5^{\circ} = 3.295^{\circ}$. The deviation for red light is $\delta_R = (\mu_R - 1)A = (1.641 - 1) 	imes 5^{\circ} = 0.641 	imes 5^{\circ} = 3.205^{\circ}$. The angular dispersion $	heta$ is the difference between the deviations: $	heta = \delta_B - \delta_R$. $	heta = 3.295^{\circ} - 3.205^{\circ} = 0.090^{\circ}$.

White light is passed through a prism of angle $5^{\circ}$. If the refractive indices for red and blue colors are $1.641$ and $1.659$ respectively,the angular dispersion between them will be..... (in $^{\circ}$)

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