When two electric bulbs of 40, W and 60, W ar | vedclass

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(D) In a parallel connection,the voltage $(V)$ across each bulb is the same.The power consumed by a bulb is given by the formula $P = \frac{V^2}{R}$.S

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The $60\, W$ bulb glows brighter.

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(D) In a parallel connection,the voltage $(V)$ across each bulb is the same.The power consumed by a bulb is given by the formula $P = \frac{V^2}{R}$.Since $P \propto \frac{1}{R}$,the bulb with lower resistance will consume more power.For a given rated voltage,$R = \frac{V^2}{P}$,which means $R \propto \frac{1}{P}$.Therefore,the $40\, W$ bulb has higher resistance than the $60\, W$ bulb.However,in parallel,the power dissipated is $P_{dissipated} = \frac{V^2}{R}$.Since the $60\, W$ bulb has lower resistance,it will dissipate more power $(P = \frac{V^2}{R})$ and thus glow brighter.

When two electric bulbs of $40\, W$ and $60\, W$ are connected in parallel,then:

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