If {R_1} and {R_2} are respectively the filam | vedclass

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(B) The power $P$ of a bulb operating at a constant voltage $V$ is given by the formula $P = \frac{V^2}{R}$.Since the voltage $V$ is the same for both

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${R_2}$ is two times ${R_1}$

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(B) The power $P$ of a bulb operating at a constant voltage $V$ is given by the formula $P = \frac{V^2}{R}$.Since the voltage $V$ is the same for both bulbs,we have $P \propto \frac{1}{R}$.This implies that $P_1 R_1 = P_2 R_2$,or $\frac{P_1}{P_2} = \frac{R_2}{R_1}$.Given $P_1 = 200 \ W$ and $P_2 = 100 \ W$,we substitute these values into the ratio:$\frac{200}{100} = \frac{R_2}{R_1}$$2 = \frac{R_2}{R_1}$Therefore,$R_2 = 2R_1$.

If ${R_1}$ and ${R_2}$ are respectively the filament resistances of a $200 \ W$ bulb and $100 \ W$ bulb designed to operate on the same voltage,then

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