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(A) The power rating of a bulb is given by $P = \frac{V^2}{R}$,where $V$ is the rated voltage and $R$ is the resistance of the bulb.For the two bulbs,

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$P_1 + P_2$ Watts

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(A) The power rating of a bulb is given by $P = \frac{V^2}{R}$,where $V$ is the rated voltage and $R$ is the resistance of the bulb.For the two bulbs,their resistances are $R_1 = \frac{V^2}{P_1}$ and $R_2 = \frac{V^2}{P_2}$.When connected in parallel to the same voltage $V$,the total power consumed $P_{total}$ is the sum of the individual powers consumed by each bulb.Since each bulb is connected to its rated voltage $V$,each bulb consumes its rated power.Therefore,$P_{total} = P_1 + P_2$.

Two electric bulbs have power ratings $P_1$ and $P_2$ at voltage $V$. They are connected in parallel to a voltage source $V$. What is the total power consumed?

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