The relationship between the electric field E | vedclass

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(B) According to Ohm's law in vector form,the current density $J$ is related to the electric field $E$ by the equation $J = \sigma E$,where $\sigma$ i

Vedclass · Accepted Answer

$E \propto J$

Vedclass · Answer

(B) According to Ohm's law in vector form,the current density $J$ is related to the electric field $E$ by the equation $J = \sigma E$,where $\sigma$ is the electrical conductivity of the material.Rearranging this equation to solve for the electric field,we get $E = J / \sigma$.Since the conductivity $\sigma$ is a constant for a given material at a constant temperature,we can conclude that $E \propto J$.Therefore,the electric field is directly proportional to the current density.

The relationship between the electric field $E$ and the current density $J$ is given by:

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