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(C) The power dissipated in a resistor connected to a constant voltage source $V$ is given by the formula $P = \frac{V^2}{R}$.Since the bulbs are conn

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$2 : 1$

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(C) The power dissipated in a resistor connected to a constant voltage source $V$ is given by the formula $P = \frac{V^2}{R}$.Since the bulbs are connected in parallel,the voltage $V$ across each bulb is the same.Therefore,the power dissipated is inversely proportional to the resistance: $P \propto \frac{1}{R}$.Given the ratio of resistances is $\frac{R_1}{R_2} = \frac{1}{2}$.The ratio of power dissipated is $\frac{P_1}{P_2} = \frac{R_2}{R_1}$.Substituting the values,we get $\frac{P_1}{P_2} = \frac{2}{1} = 2 : 1$.

Two electric bulbs have resistances in the ratio $1 : 2$. If they are connected in parallel to a constant voltage source,the ratio of power dissipated in them will be:

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