$A$ galvanometer coil has a resistance of $990 \,\Omega$. It shows a full-scale deflection for a current of $10 \,mA$. Calculate the value of the shunt resistance required to convert it into an ammeter of range $1 \,A$.

$A$ voltmeter of $250 mV$ range having a resistance of $10 \Omega$ is converted into an ammeter of $250 mA$ range. The value of the necessary shunt is (nearly): (in $\Omega$)

$A$ galvanometer has a resistance $100 \ \Omega$ and its full-scale deflection current is $10 \ mA$. What is the value of the shunt resistance required so that it can measure current up to $10 \ A$?

$A$ moving coil galvanometer has $150$ equal divisions. Its current sensitivity is $10$ divisions per milliampere and voltage sensitivity is $2$ divisions per millivolt. In order that each division reads $1 \, V$,the resistance in $\Omega$ needed to be connected in series with the coil will be

$A$ galvanometer of resistance $G$ can be converted into a voltmeter of range $V$ by connecting a resistance $R$ in series with it. The series resistance required to change its range to $\frac{V}{3}$ is

The sensitivity of a galvanometer is $60 \text{ division/A}$. When a shunt is used,its sensitivity becomes $10 \text{ division/A}$. If the galvanometer is of resistance $20 \ \Omega$,the value of shunt used is (in $\Omega$)