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(C) Let $n$ be the total number of resistors used in the circuit.Let the equivalent resistance of the combination be $R_{eq} = 5 \, \Omega$ and the to

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$8$

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(C) Let $n$ be the total number of resistors used in the circuit.Let the equivalent resistance of the combination be $R_{eq} = 5 \, \Omega$ and the total current be $I_{total} = 4 \, 	ext{A}$.Each resistor has $R = 10 \, \Omega$ and $I_{max} = 1 \, 	ext{A}$.The power dissipated by the equivalent circuit is $P_{eq} = I_{total}^2 	imes R_{eq} = (4)^2 	imes 5 = 16 	imes 5 = 80 \, 	ext{W}$.The power capacity of each individual resistor is $P_{res} = I_{max}^2 	imes R = (1)^2 	imes 10 = 10 \, 	ext{W}$.Since the total power must be supplied by the $n$ resistors,we have $P_{eq} = n 	imes P_{res}$.$80 = n 	imes 10$.Therefore,$n = 8$.

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