The outer and inner radii of a hollow cylinde | vedclass

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Question

(A) The thickness of the wall $(t)$ is given by the difference between the outer radius $(r_1)$ and the inner radius $(r_2)$.$t = r_1 - r_2 = 4.23 	e

Vedclass · Accepted Answer

$(0.34 \pm 0.02) 	ext{ cm}$

Vedclass · Answer

(A) The thickness of the wall $(t)$ is given by the difference between the outer radius $(r_1)$ and the inner radius $(r_2)$.$t = r_1 - r_2 = 4.23 	ext{ cm} - 3.89 	ext{ cm} = 0.34 	ext{ cm}$.When subtracting two quantities,the absolute errors are added.$\Delta t = \Delta r_1 + \Delta r_2 = 0.01 	ext{ cm} + 0.01 	ext{ cm} = 0.02 	ext{ cm}$.Therefore,the thickness of the wall is $(t \pm \Delta t) = (0.34 \pm 0.02) 	ext{ cm}$.

The outer and inner radii of a hollow cylinder are $(4.23 \pm 0.01) \text{ cm}$ and $(3.89 \pm 0.01) \text{ cm}$ respectively. What is the thickness of the wall of the cylinder?

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