(D) For the first minimum in single-slit diffraction,the condition is given by: $a \sin \theta = n \lambda$ For the first minimum,$n = 1$. So,$a \sin

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(D) For the first minimum in single-slit diffraction,the condition is given by: $a \sin \theta = n \lambda$ For the first minimum,$n = 1$. So,$a \sin \theta = \lambda$ $a = \frac{\lambda}{\sin \theta}$ Given: $\lambda = 650 \ nm = 650 \times 10^{-9} \ m$ and $\theta = 30^\circ$. Substituting the values: $a = \frac{650 \times 10^{-9}}{\sin 30^\circ}$ $a = \frac{650 \times 10^{-9}}{0.5}$ $a = 1300 \times 10^{-9} \ m$ $a = 1.3 \times 10^{-6} \ m$

Class 12 Physics Wave Optics Single Slit Diffraction of Light

Medium

$A$ slit of width $a$ is illuminated by monochromatic light of wavelength $650 \ nm$. The value of the slit width $a$ when the first minimum is formed at a diffraction angle of $30^\circ$ is:

A
$1.4 \times 10^{-5} \ m$
B
$1.3 \times 10^{-3} \ m$
C
$1.3 \times 10^3 \ m$
D
$1.3 \times 10^{-6} \ m$

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Class 12

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Wave Optics

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Single Slit Diffraction of Light

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$A$ diffraction pattern is obtained using a beam of red light. If the red light is replaced by blue light,then:

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In an experiment of single slit diffraction pattern,the first minimum for red light coincides with the first maximum of some other wavelength. If the wavelength of red light is $6600\,\mathring{A}$,then the wavelength of the first maximum will be.....$\mathring{A}$

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$A$ slit of width $a$ is illuminated by light of wavelength $\lambda$. The linear separation between $1^{st}$ and $3^{rd}$ minima in the diffraction pattern produced on a screen placed at a distance $D$ from the slit system is . . . . . . .

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In a single slit diffraction experiment, the width of the slit is reduced. What happens to the linear width of the principal maxima?

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$A$ slit of width $a$ is illuminated by monochromatic light of wavelength $650 \ nm$. The value of the slit width $a$ when the first minimum is formed at a diffraction angle of $30^\circ$ is:

Similar Questions

$A$ plane wave front of wavelength $\lambda$ is incident on a single slit of width $b$. What is the angular width of the secondary maximum?

$A$ diffraction pattern is obtained using a beam of red light. If the red light is replaced by blue light,then:

In an experiment of single slit diffraction pattern,the first minimum for red light coincides with the first maximum of some other wavelength. If the wavelength of red light is $6600\,\mathring{A}$,then the wavelength of the first maximum will be.....$\mathring{A}$

$A$ slit of width $a$ is illuminated by light of wavelength $\lambda$. The linear separation between $1^{st}$ and $3^{rd}$ minima in the diffraction pattern produced on a screen placed at a distance $D$ from the slit system is . . . . . . .

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