A student measures the focal length of a conv | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The lens formula is given by $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.In the standard sign convention for a convex lens,the object distance $u$ i

Vedclass · Accepted Answer

Vedclass · Answer

(B) The lens formula is given by $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.In the standard sign convention for a convex lens,the object distance $u$ is negative $(-u)$ and the image distance $v$ is positive $(+v)$.Substituting these into the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{-u} = \frac{1}{v} + \frac{1}{u}$.Rearranging for $v$: $\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{u-f}{fu}$.Thus,$v = \frac{fu}{u-f}$.As $u$ increases from $f$ to $\infty$,$v$ decreases from $\infty$ to $f$. This represents a rectangular hyperbola in the first quadrant,which corresponds to the graph shown in option $B$.

$A$ student measures the focal length of a convex lens by obtaining an image of an object pin at a distance '$v$' from the lens,with the object placed at a distance '$u$' from the lens. What will the graph between '$u$' and '$v$' look like?

Similar Questions

The radius of the convex surface of a plano-convex lens is $20 \ cm$ and the refractive index of the material of the lens is $1.5$. The focal length of the lens is......$cm$.

$A$ convex lens has its radii of curvature equal. The focal length of the lens is $f$. If it is divided vertically into two identical plano-convex lenses by cutting it, then the focal length of the plano-convex lens is ($\mu =$ the refractive index of the material of the lens).

Where should an object be placed on the axis of a convex lens of focal length $8 \ cm$ so as to achieve magnification of $-4$ (in $cm$)? (Distances are measured from the optic centre of the lens)

An object of height $1.5 \ cm$ is placed on the axis of a convex lens of focal length $25 \ cm$. $A$ real image is formed at a distance of $75 \ cm$ from the lens. The size of the image will be........$cm$.

$A$ convex lens is made of glass $(\mu_g = 1.5)$ and has a focal length of $4 \, cm$ in air. If it is immersed in water $(\mu_w = 1.33)$,what will be its new focal length in $cm$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module