In the interference pattern of white light, w | vedclass

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(A) The path difference at the center of the interference pattern is zero for all wavelengths. Therefore, all colors overlap at the center, forming a

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Violet

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(A) The path difference at the center of the interference pattern is zero for all wavelengths. Therefore, all colors overlap at the center, forming a white central fringe. The bright fringe closest to the center is the first order fringe. Since the position of the $n^{th}$ bright fringe is given by $y_n = \frac{n \lambda D}{d}$, the fringe width and position are directly proportional to the wavelength $\lambda$. Because the wavelength of violet light $(\lambda_{violet} \approx 400 	ext{ nm})$ is the smallest among the visible spectrum, the violet fringe appears closest to the central white fringe.

In the interference pattern of white light, what is the color of the bright fringe closest to the center?

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