The diffraction of light starts from an obstacle (edge). It depends on ...

  • A
    Size of the obstacle (edge)
  • B
    Size of the obstacle (edge) and wavelength
  • C
    Distance of the screen from the obstacle (edge) and wavelength
  • D
    Size of the obstacle and its distance from the screen

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Similar Questions

In a single slit diffraction pattern,the distance between the plane of the slit and the screen is $1.3 \ m$. The width of the slit is $0.65 \ mm$ and the second maximum is formed at a distance of $2.6 \ mm$ from the center of the screen. The wavelength of light used is: (in $Å$)

"The person standing behind the open door inside the room can hear the voice of the person standing on the other side of the door but they cannot see each other". Give an experiment based on the diffraction for this statement.

In the case of Fraunhofer diffraction due to a single slit,the intensity of the central maximum is $I_0$. If the width of the slit is doubled,what will be the new intensity of the central maximum?

Angular width of the central maximum of a diffraction pattern due to a single slit does not depend upon:

The phenomenon that explains why light waves do not travel in a straight line is known as .......

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