If the $n^{th}$ term of a sequence is $T_n = 2n - 1$,then the sum of $n$ terms $S_n = \dots$

  • A
    $n^2$
  • B
    $\frac{n(n+1)}{2}$
  • C
    $\frac{n(n+1)(2n+1)}{6}$
  • D
    $n+2$

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