In how many ways can 6 examination papers be | vedclass

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Question

(B) The total number of ways to arrange $6$ papers is $6! = 720$.To find the number of ways where the best and worst papers are together,we treat them

Vedclass · Accepted Answer

$480$

Vedclass · Answer

(B) The total number of ways to arrange $6$ papers is $6! = 720$.To find the number of ways where the best and worst papers are together,we treat them as a single unit. This leaves us with $5$ units to arrange,which can be done in $5!$ ways. The two papers within the unit can be arranged in $2!$ ways.Number of ways where they are together $= 5! 	imes 2! = 120 	imes 2 = 240$.Number of ways where they are never together $= 	ext{Total ways} - 	ext{Ways together} = 720 - 240 = 480$.

In how many ways can $6$ examination papers be arranged so that the best and the worst papers are never together?

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