If $C$ is the midpoint of $AB$ and $P$ is any point outside $AB$,then:

  • A
    $\overrightarrow{PA} + \overrightarrow{PB} = \overrightarrow{PC}$
  • B
    $\overrightarrow{PA} + \overrightarrow{PB} = 2\overrightarrow{PC}$
  • C
    $\overrightarrow{PA} + \overrightarrow{PB} + \overrightarrow{PC} = 0$
  • D
    $\overrightarrow{PA} + \overrightarrow{PB} + 2\overrightarrow{PC} = 0$

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