If the vertices of $\Delta ABC$ are $A(1, -1, 2)$,$B(2, 0, -1)$,and $C(0, 2, 1)$,then what is the area of the triangle?

  • A
    $\sqrt{6}$
  • B
    $2\sqrt{6}$
  • C
    $3\sqrt{6}$
  • D
    $4\sqrt{6}$

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