If a die is thrown 2 times,what is the probab | vedclass

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(A) When a die is thrown $2$ times,the total number of outcomes is $6^2 = 36$.Let $E$ be the event of getting $4$ at least once.It is easier to calcul

Vedclass · Accepted Answer

$\frac{11}{36}$

Vedclass · Answer

(A) When a die is thrown $2$ times,the total number of outcomes is $6^2 = 36$.Let $E$ be the event of getting $4$ at least once.It is easier to calculate the probability of the complement event $E'$,which is the event of not getting $4$ in either throw.The probability of not getting $4$ in one throw is $\frac{5}{6}$.Since the two throws are independent,the probability of not getting $4$ in both throws is $P(E') = \frac{5}{6} 	imes \frac{5}{6} = \frac{25}{36}$.Therefore,the probability of getting $4$ at least once is $P(E) = 1 - P(E') = 1 - \frac{25}{36} = \frac{11}{36}$.

If a die is thrown $2$ times,what is the probability of getting $4$ at least once?

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