The probability that the sum of 2 numbers cho | vedclass

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(C) The total number of ways to choose $2$ numbers from $30$ consecutive integers is $n = \binom{30}{2} = \frac{30 	imes 29}{2} = 15 	imes 29$.The s

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$\frac{15}{29}$

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(C) The total number of ways to choose $2$ numbers from $30$ consecutive integers is $n = \binom{30}{2} = \frac{30 	imes 29}{2} = 15 	imes 29$.The sum of two numbers is odd if and only if one number is even and the other is odd.In $30$ consecutive integers,there are $15$ even and $15$ odd numbers.The number of ways to choose one even and one odd number is $r = \binom{15}{1} 	imes \binom{15}{1} = 15 	imes 15$.The required probability is $P = \frac{15 	imes 15}{15 	imes 29} = \frac{15}{29}$.

The probability that the sum of $2$ numbers chosen at random from $30$ consecutive integers is odd is..........

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