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(D) The total number of ways to select $2$ numbers from $6$ numbers without replacement is $P(6, 2) = 6 	imes 5 = 30$.Let the two numbers be $x$ and

Vedclass · Accepted Answer

$\frac{4}{5}$

Vedclass · Answer

(D) The total number of ways to select $2$ numbers from $6$ numbers without replacement is $P(6, 2) = 6 	imes 5 = 30$.Let the two numbers be $x$ and $y$. We want the probability that $\min(x, y) It is easier to calculate the complement: the probability that $\min(x, y) \geq 4$.This means both numbers must be chosen from the set $\{4, 5, 6\}$.The number of ways to choose $2$ numbers from $\{4, 5, 6\}$ is $P(3, 2) = 3 	imes 2 = 6$.The probability that $\min(x, y) \geq 4$ is $\frac{6}{30} = \frac{1}{5}$.Therefore,the probability that $\min(x, y) < 4$ is $1 - \frac{1}{5} = \frac{4}{5}$.

$A$. Probability that none of the balls is white	$I$. $\frac{1}{70}$
$B$. Probability of getting $2$ white and $1$ blue ball	$II$. $\frac{6}{35}$
$C$. Probability of getting $2$ blue and $1$ white ball	$III$. $\frac{13}{20}$
$D$. Probability of getting $1$ red, $1$ white and $1$ blue ball	$IV$. $\frac{1}{10}$

Two numbers are selected randomly from the set $S = \{ 1, 2, 3, 4, 5, 6 \}$ without replacement one by one. The probability that the minimum of the two numbers is less than $4$ is

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