If the sum of squares of deviations of 10 obs | vedclass

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(D) Given: $\Sigma (x_i - \bar{x})^2 = 250$,$n = 10$,$\bar{x} = 50$. The variance $\sigma^2$ is given by $\frac{1}{n} \Sigma (x_i - \bar{x})^2 = \frac

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None of these

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(D) Given: $\Sigma (x_i - \bar{x})^2 = 250$,$n = 10$,$\bar{x} = 50$. The variance $\sigma^2$ is given by $\frac{1}{n} \Sigma (x_i - \bar{x})^2 = \frac{250}{10} = 25$. The standard deviation $\sigma = \sqrt{25} = 5$. The coefficient of variation $(CV)$ is calculated as $CV = \frac{\sigma}{\bar{x}} 	imes 100$. $CV = \frac{5}{50} 	imes 100 = 0.1 	imes 100 = 10\%$. Since $10\%$ is not among the options $A, B, C$,the correct choice is $D$.

$x_i$	$4$	$8$	$11$	$17$	$20$	$24$	$32$
$f_i$	$3$	$5$	$9$	$5$	$4$	$3$	$1$

If the sum of squares of deviations of $10$ observations from their mean $50$ is $250$,what is the coefficient of variation?

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