The mean deviation about the median for the o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) First,we arrange the observations in ascending order:$34, 38, 42, 44, 46, 48, 54, 55, 63, 70$Here,$n = 10$ (even).The median $(M) = \frac{(\frac{n

Vedclass · Accepted Answer

$8.6$

Vedclass · Answer

(B) First,we arrange the observations in ascending order:$34, 38, 42, 44, 46, 48, 54, 55, 63, 70$Here,$n = 10$ (even).The median $(M) = \frac{(\frac{n}{2})^{th} 	ext{ term} + (\frac{n}{2} + 1)^{th} 	ext{ term}}{2} = \frac{46 + 48}{2} = 47$.Now,calculate the sum of absolute deviations from the median:$\Sigma |x_i - M| = |34-47| + |38-47| + |42-47| + |44-47| + |46-47| + |48-47| + |54-47| + |55-47| + |63-47| + |70-47|$$= 13 + 9 + 5 + 3 + 1 + 1 + 7 + 8 + 16 + 23 = 86$.Mean deviation about the median $= \frac{\Sigma |x_i - M|}{n} = \frac{86}{10} = 8.6$.

Class interval	$0-4$	$4-8$	$8-12$	$12-16$	$16-20$
Frequency	$4$	$6$	$8$	$5$	$2$

Class Interval	$0-4$	$4-8$	$8-12$	$12-16$
Frequency	$4$	$3$	$2$	$1$

$x_i$	$5$	$10$	$15$	$20$	$25$
$f_i$	$7$	$4$	$6$	$3$	$5$

The mean deviation about the median for the observations $70, 42, 63, 34, 44, 54, 55, 46, 38, 48$ is:

Similar Questions

Calculate the mean deviation about the mean for the following frequency distribution:
Class interval $0-4$ $4-8$ $8-12$ $12-16$ $16-20$
Frequency $4$ $6$ $8$ $5$ $2$

The mean deviation about the mean for the following data is

Class Interval $0-4$ $4-8$ $8-12$ $12-16$

Frequency $4$ $3$ $2$ $1$

Find the mean deviation about the median for the given data: $340, 150, 210, 240, 300, 310, 320$.

In a series of $3n$ observations,if $n$ observations are equal to $a$ and the remaining $2n$ observations are equal to $-2a$,then the mean deviation of the observations about their mean is:

Find the mean deviation about the mean for the given data:

$x_i$ $5$ $10$ $15$ $20$ $25$

$f_i$ $7$ $4$ $6$ $3$ $5$

Vedclass Test Series

Exam Paper Generator

Online Exam Module