A scientist weighs 30 fish. Their mean weight | vedclass

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(B) Let the original weights be $x_i$. The given mean is $\bar{x} = 30 	ext{ g}$ and the standard deviation is $\sigma = 2 	ext{ g}$.Since every wei

Vedclass · Accepted Answer

$32, 2$

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(B) Let the original weights be $x_i$. The given mean is $\bar{x} = 30 	ext{ g}$ and the standard deviation is $\sigma = 2 	ext{ g}$.Since every weight was recorded $2 	ext{ g}$ less than the actual weight,the corrected weights are $y_i = x_i + 2$.The new mean is $\bar{y} = \bar{x} + 2 = 30 + 2 = 32 	ext{ g}$.Standard deviation is independent of the change of origin. Adding a constant to each observation does not change the dispersion of the data.Therefore,the corrected standard deviation remains $\sigma = 2 	ext{ g}$.The correct mean and standard deviation are $32 	ext{ g}$ and $2 	ext{ g}$ respectively.

Class Interval	$0$-$5$	$5$-$10$	$10$-$15$	$15$-$20$	$20$-$25$
Frequency	$4$	$1$	$10$	$3$	$2$

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