(B) According to Einstein's photoelectric equation: $E_k = \frac{hc}{\lambda} - \phi$,where $\phi$ is the work function.For $\lambda_1 = 3000 \ \mathr

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(B) According to Einstein's photoelectric equation: $E_k = \frac{hc}{\lambda} - \phi$,where $\phi$ is the work function.For $\lambda_1 = 3000 \ \mathring{A}$,$E_{k1} = 0.5 \ eV$.Using $hc \approx 12400 \ eV \cdot \mathring{A}$:$0.5 = \frac{12400}{3000} - \phi$$0.5 = 4.13 - \phi \implies \phi = 3.63 \ eV$.Now,for $\lambda_2 = 2000 \ \mathring{A}$:$E_{k2} = \frac{12400}{2000} - 3.63$$E_{k2} = 6.2 - 3.63 = 2.57 \ eV$.Since $2.57 \ eV > 0.5 \ eV$,the energy of the emitted electron is greater than $0.5 \ eV$.

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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When a photon of wavelength $3000 \ \mathring{A}$ is incident on a metal surface,the energy of the emitted electron is $0.5 \ eV$. If a photon of wavelength $2000 \ \mathring{A}$ is incident on the same metal surface,the energy of the emitted electron will be:

A
$0.5 \ eV$
B
greater than $0.5 \ eV$
C
less than $0.5 \ eV$
D
none of the above

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Dual Nature of Radiation and matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

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$A$ beam of light falls on a metal surface such that photo-electrons are generated. If the power of the light source starts to decrease linearly with time $t$, then the variation of the photocurrent $I$ and the magnitude of the stopping potential $|V|$ with time is best represented by:

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When a photon of wavelength $3000 \ \mathring{A}$ is incident on a metal surface,the energy of the emitted electron is $0.5 \ eV$. If a photon of wavelength $2000 \ \mathring{A}$ is incident on the same metal surface,the energy of the emitted electron will be:

Similar Questions

In an experiment to study the photoelectric effect,the observed variation of stopping potential $(V_0)$ with the frequency $(\nu)$ of incident radiation is as shown in the figure. The slope and $y$-intercept are respectively

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface,having work function $5.01 \, eV$,when ultraviolet light of $200 \, nm$ falls on it,must be ............... $V$.

The work functions for metals $A, B$ and $C$ are $1.92 eV, 2.0 eV$ and $5 eV$ respectively. According to Einstein's photoelectric equation,which of these metals will emit photoelectrons for an incident radiation of wavelength $4100 \mathring{A}$?

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