An electric bulb of 100 W power emits photon | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The power of the bulb is $P = 100 \ W$,which means it emits $100 \ J$ of energy per second.The energy of a single photon is given by the formula $

Vedclass · Accepted Answer

$2.06 	imes 10^{20}$

Vedclass · Answer

(C) The power of the bulb is $P = 100 \ W$,which means it emits $100 \ J$ of energy per second.The energy of a single photon is given by the formula $E = \frac{hc}{\lambda}$.Given values: $h = 6.63 	imes 10^{-34} \ J \cdot s$,$c = 3 	imes 10^8 \ m/s$,and $\lambda = 410 	imes 10^{-9} \ m$.Substituting these values,the energy of one photon is $E = \frac{6.63 	imes 10^{-34} 	imes 3 	imes 10^8}{410 	imes 10^{-9}} \approx 4.85 	imes 10^{-19} \ J$.The number of photons emitted per second $(n)$ is calculated as $n = \frac{P}{E}$.$n = \frac{100}{4.85 	imes 10^{-19}} \approx 2.06 	imes 10^{20}$ photons per second.

An electric bulb of $100 \ W$ power emits photons of wavelength $410 \ nm$ per second. The number of photons emitted per second is: $(h = 6.63 \times 10^{-34} \ J \cdot s, c = 3 \times 10^8 \ m/s)$

Similar Questions

$A$ photon is associated with .........

Monochromatic light of frequency $6 \times 10^{14} \,Hz$ is produced by a laser. The power emitted is $2 \times 10^{-3} \,W$. The energy of the photon in this light beam is . . . . . . eV.

The number of photons emitted per second by a bulb of $66 \ W$ power emitting waves of wavelength $600 \ nm$ is . . . . . . . $(h = 6.6 \times 10^{-34} \ J \cdot s)$

The frequency of a photon with energy $100 \ eV$ is ........... $Hz$. (Given: $h = 6.62 \times 10^{-34} \ J \cdot s$,$1 \ eV = 1.6 \times 10^{-19} \ J$)

$A$ radio station broadcasts at a wavelength of $300 \ m$. If the radiating power of the transmitter is $10 \ kW$,then the number of photons emitted per second is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module