Find the ratio of the de Broglie wavelength of an oxygen molecule at $21^oC$ to that of a nitrogen molecule at $63^oC$.

If the velocity of an electron increases,what will be the change in its de Broglie wavelength?

$A$ proton and an electron initially at rest are accelerated by the same potential difference. Assuming that a proton is $2000$ times heavier than an electron, what will be the relation between the de Broglie wavelength of the proton $(\lambda_{p})$ and that of the electron $(\lambda_{e})$?

$A$ proton and an alpha particle are accelerated under the same potential difference. The ratio of de-Broglie wavelengths of the proton and the alpha particle is

If an electron and a photon propagate in the form of waves having the same wavelength,it implies that they have the same

If the kinetic energy of an electron is increased four times,the wavelength of the de-Broglie wave associated with it would become