If an electron and a photon propagate in the form of waves having the same wavelength,it implies that they have the same

  • A
    Energy
  • B
    Momentum
  • C
    Velocity
  • D
    Angular momentum

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The de-Broglie wavelength of a particle accelerated with $150 \ V$ potential is $10^{-10} \ m$. If it is accelerated by $600 \ V$ potential difference,its wavelength will be: ............... $\mathring{A}$

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Two electrons are moving with the same speed $v$. One electron enters a region of uniform electric field while the other enters a region of uniform magnetic field. After some time,if the de-Broglie wavelengths of the two are $\lambda_1$ and $\lambda_2$,then:

The de-Broglie wavelength associated with a particle of mass $m$ moving with velocity $v$ is:

$A$ proton is accelerated through $225 \,V$. Its de Broglie wavelength is ........ $nm$.

An electron of mass $m$ and a photon have the same energy $E$. The ratio of the de-Broglie wavelengths associated with them is:

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