The wavelength of an X-ray photon is 0.01 ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The wavelength of the photon is given by $\lambda = 0.01 \ \mathring A = 0.01 	imes 10^{-10} \ m = 10^{-12} \ m$. The momentum $p$ of a photon is

Vedclass · Accepted Answer

$6.6 	imes 10^{-22}$

Vedclass · Answer

(A) The wavelength of the photon is given by $\lambda = 0.01 \ \mathring A = 0.01 	imes 10^{-10} \ m = 10^{-12} \ m$. The momentum $p$ of a photon is related to its wavelength $\lambda$ by the de Broglie relation: $p = \frac{h}{\lambda}$. Substituting the values,where Planck's constant $h = 6.63 	imes 10^{-34} \ J \ s$ (approximated as $6.6 	imes 10^{-34} \ J \ s$ for this calculation): $p = \frac{6.6 	imes 10^{-34}}{10^{-12}} = 6.6 	imes 10^{-22} \ kg \ m/s$.

The wavelength of an $X$-ray photon is $0.01 \ \mathring A$. Its momentum in $kg \ m/s$ is .........

Similar Questions

How are $X-$rays produced?

When an $X$-ray tube operates at $60 \ kV$,the observed tube current is $50 \ mA$. Assuming that the total energy of the electrons is converted into heat,the rate of heat production at the anode in $cal/s$ is:

The minimum wavelength of $X$-rays produced by electrons accelerated by a potential difference of $V$ volts is equal to:

The energy of an $X$-ray photon of wavelength $1.65 \mathring{A}$ is ....... $keV$. $(h = 6.6 \times 10^{-34} \ J \cdot s, \ c = 3 \times 10^8 \ m/s, \ 1 \ eV = 1.6 \times 10^{-19} \ J)$ (in $.5$)

Penetrating power of $X$-rays increases with an increase in

Vedclass Test Series

Exam Paper Generator

Online Exam Module