When a photon of energy $hv$ is incident on an aluminum plate with a work function $E_0$,the maximum kinetic energy of the emitted photoelectrons is $K$. If the frequency of the incident radiation is doubled,the maximum kinetic energy of the emitted photoelectrons will be .......

  • A
    $K$
  • B
    $K + hv$
  • C
    $K + E_0$
  • D
    $2K$

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