If the kinetic energy of a free electron is doubled,by what factor does its de Broglie wavelength change?

If an electron and a proton have the same de-Broglie wavelength,then the kinetic energy of the electron is

What should be the order of arrangement of de-Broglie wavelength of an electron $(\lambda_{e})$,an $\alpha$-particle $(\lambda_{\alpha})$,and a proton $(\lambda_{p})$,given that all have the same kinetic energy?

The kinetic energy of an electron is tripled,then the de-Broglie wavelength associated with it will change by a factor of:

$A$ particle of mass $4M$ at rest disintegrates into two particles of mass $M$ and $3M$ respectively,having non-zero velocities. The ratio of the de-Broglie wavelength of the particle of mass $M$ to that of mass $3M$ will be:

$A$ particle is travelling $4$ times as fast as an electron. Assuming the ratio of the de-Broglie wavelength of the particle to that of the electron is $2:1$,the mass of the particle is: