(B) The $rms$ speed is given by the formula $u = \sqrt{\frac{3RT}{M}}$.Initially,for $N_2$ molecules,$u = \sqrt{\frac{3RT}{M}}$,where $M$ is the molar

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(B) The $rms$ speed is given by the formula $u = \sqrt{\frac{3RT}{M}}$.Initially,for $N_2$ molecules,$u = \sqrt{\frac{3RT}{M}}$,where $M$ is the molar mass of $N_2$.When the temperature is doubled $(T' = 2T)$ and $N_2$ dissociates into $N$ atoms,the new molar mass becomes $M' = M/2$.The new $rms$ speed $u'$ is given by $u' = \sqrt{\frac{3R(2T)}{M/2}} = \sqrt{\frac{3R(4T)}{M}} = 2 \sqrt{\frac{3RT}{M}} = 2u$.

Class 11 Chemistry States of Matter Molecular speeds

Medium

The $rms$ speed of $N_2$ molecules in a gas is $u$. If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atoms,what will be the new $rms$ speed?

A
$u/2$
B
$2u$
C
$4u$
D
$14u$

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States of Matter

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Molecular speeds

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The $rms$ speed of $N_2$ molecules in a gas is $u$. If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atoms,what will be the new $rms$ speed?

Similar Questions

The $rms$ velocity of hydrogen is $\sqrt{7}$ times the $rms$ velocity of nitrogen. If the temperature of the gas is $T$,then which of the following is true?

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