(C) Let the oxidation number of carbon be $X$.In $CH_2O$,the oxidation number of hydrogen $(H)$ is $+1$ and oxygen $(O)$ is $-2$.The sum of oxidation

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(C) Let the oxidation number of carbon be $X$.In $CH_2O$,the oxidation number of hydrogen $(H)$ is $+1$ and oxygen $(O)$ is $-2$.The sum of oxidation numbers in a neutral molecule is $0$.$X + 2(+1) + 1(-2) = 0$$X + 2 - 2 = 0$$X = 0$Therefore,the oxidation number of carbon in $CH_2O$ is $0$.