The correct order of N compounds in their dec | vedclass

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(A) To find the decreasing order of oxidation states,we calculate the oxidation state of nitrogen $(N)$ in each compound:$1$. In $HNO_{3}$: $1 + x + 3

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$HNO_{3}, NO, N_{2}, NH_{4}Cl$

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(A) To find the decreasing order of oxidation states,we calculate the oxidation state of nitrogen $(N)$ in each compound:$1$. In $HNO_{3}$: $1 + x + 3(-2) = 0 \implies x = +5$$2$. In $NO$: $x + (-2) = 0 \implies x = +2$$3$. In $N_{2}$: The oxidation state of an element in its free state is $0$.$4$. In $NH_{4}Cl$: $x + 4(1) + (-1) = 0 \implies x + 3 = 0 \implies x = -3$Comparing the values: $+5 > +2 > 0 > -3$.Therefore,the correct order is $HNO_{3} > NO > N_{2} > NH_{4}Cl$.

The correct order of $N$ compounds in their decreasing order of oxidation states is:

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