Which of the following is the weakest reducin | vedclass

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(B) The reducing power of alkali metals is determined by their standard electrode potential $(E^\circ)$.$Li$ has the most negative $E^\circ$ value,mak

Vedclass · Accepted Answer

$Na$

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(B) The reducing power of alkali metals is determined by their standard electrode potential $(E^\circ)$.$Li$ has the most negative $E^\circ$ value,making it the strongest reducing agent in aqueous solution due to its high hydration energy.Among the given options $(Li, Na, K, Rb)$,the reducing power generally increases down the group due to the decrease in ionization enthalpy,but in aqueous solution,$Li$ is the strongest. However,comparing the standard reduction potentials $(E^\circ)$ for $M^+/M$,the values are: $Li^+/Li = -3.04 \ V$,$Rb^+/Rb = -2.93 \ V$,$K^+/K = -2.93 \ V$,$Na^+/Na = -2.71 \ V$.Since $Na$ has the least negative reduction potential,it acts as the weakest reducing agent among the given options.

Which of the following is the weakest reducing agent?

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