For a redox reaction,Oxi + ne^- rightarrow Re | vedclass

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Question

(B) The Nernst equation for a general redox reaction $aA + bB \rightarrow cC + dD$ is given by $E_{cell} = E_{cell}^\circ - \frac{RT}{nF} \ln Q$,where

Vedclass · Accepted Answer

$E_{cell} = E_{cell}^\circ - \frac{RT}{nF} \ln \frac{[Red]}{[Oxi]}$

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(B) The Nernst equation for a general redox reaction $aA + bB \rightarrow cC + dD$ is given by $E_{cell} = E_{cell}^\circ - \frac{RT}{nF} \ln Q$,where $Q$ is the reaction quotient.For the half-reaction $Oxi + ne^- \rightarrow Red$,the reaction quotient $Q$ is defined as $\frac{[Red]}{[Oxi]}$.Substituting this into the Nernst equation,we get $E_{cell} = E_{cell}^\circ - \frac{RT}{nF} \ln \frac{[Red]}{[Oxi]}$.Alternatively,using the property of logarithms,$-\ln \frac{[Red]}{[Oxi]} = \ln \frac{[Oxi]}{[Red]}$,so $E_{cell} = E_{cell}^\circ + \frac{RT}{nF} \ln \frac{[Oxi]}{[Red]}$.

For a redox reaction,$Oxi + ne^- \rightarrow Red$,what is the correct form of the Nernst equation?

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