For a galvanic cell reaction at $25^{\circ}C$ with $n = 4$,the standard $emf$ is $0.295 \ V$. What is the equilibrium constant for the reaction? $(F = 96500 \ C \ mol^{-1}; R = 8.314 \ J \ K^{-1} \ mol^{-1})$

  • A
    $1.0 \times 10^{20}$
  • B
    $2.0 \times 10^{11}$
  • C
    $4.0 \times 10^{12}$
  • D
    $1.0 \times 10^{2}$

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The standard cell potential of a cell reaction involving the transfer of $2$ electrons at $25^{\circ}C$ is $0.295 \ V$. What is its equilibrium constant at $25^{\circ}C$?

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