Which of the following species has the highes | vedclass

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(C) The bond order is calculated using the formula: $	ext{Bond Order} = \frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$

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$O_2^+$

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(C) The bond order is calculated using the formula: $	ext{Bond Order} = \frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.$1. O_2$ ($16$ electrons): Configuration is $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_z)^2(\pi 2p_x)^2(\pi 2p_y)^2(\pi^* 2p_x)^1(\pi^* 2p_y)^1$. Bond order $= \frac{10 - 6}{2} = 2$.$2. O_2^-$ ($17$ electrons): Configuration adds one electron to $\pi^* 2p_y$. Bond order $= \frac{10 - 7}{2} = 1.5$.$3. O_2^+$ ($15$ electrons): Configuration removes one electron from $\pi^* 2p_y$. Bond order $= \frac{10 - 5}{2} = 2.5$.$4. O_2^{2-}$ ($18$ electrons): Configuration adds two electrons to $\pi^* 2p_x$ and $\pi^* 2p_y$. Bond order $= \frac{10 - 8}{2} = 1$.Comparing the values,$O_2^+$ has the highest bond order of $2.5$.

Which of the following species has the highest bond order?

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