The increasing order of bond order of $O_2, O_2^+, O_2^-$,and $O_2^{2-}$ is:
- A$O_2^+, O_2, O_2^-, O_2^{2-}$
- B$O_2^{2-}, O_2^-, O_2^+, O_2$
- C$O_2, O_2^+, O_2^-, O_2^{2-}$
- D$O_2^{2-}, O_2^-, O_2, O_2^+$
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Similar Questions
Match the molecules in List-$I$ with their respective bond orders in List-$II$.
List-$I$ List-$II$ $A. Li_2$ $i. 3$ $B. N_2$ $ii. 1.5$ $C. Be_2$ $iii. 1.0$ $D. O_2$ $iv. 0$ $v. 2$
| List-$I$ | List-$II$ |
|---|---|
| $A. Li_2$ | $i. 3$ |
| $B. N_2$ | $ii. 1.5$ |
| $C. Be_2$ | $iii. 1.0$ |
| $D. O_2$ | $iv. 0$ |
| $v. 2$ |
The bond order is maximum in
MediumAIIMS 1983
View SolutionWhich of the following concepts is $NOT$ part of the valence bond theory $(VBT)$?
What is the effect of the following processes on the bond order in $N_{2}$ and $O_{2}$?
$(A)$ $N_{2} \to N_{2}^{+} + e^{-}$
$(B)$ $O_{2} \to O_{2}^{+} + e^{-}$
$(A)$ $N_{2} \to N_{2}^{+} + e^{-}$
$(B)$ $O_{2} \to O_{2}^{+} + e^{-}$
Medium
View SolutionThe correct pair of species with $(A)$ the highest bond order and $(B)$ diamagnetic character is
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