The bond order is maximum in
- A$O_2$
- B$O_2^{-}$
- C$O_2^{+}$
- D$O_2^{2-}$
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Similar Questions
Between $1s-1s$ and $1s-2s$ combinations,which one does not form a molecular orbital? Why?
Medium
View SolutionMatch List-$I$ with List-$II$.
List-$I$ List-$II$ $A$. $\Psi_{MO} = \Psi_{A} - \Psi_{B}$ $I$. Dipole moment $B$. $\mu = Q \times r$ $II$. Bonding molecular orbital $C$. $\frac{N_{b} - N_{a}}{2}$ $III$. Anti-bonding molecular orbital $D$. $\Psi_{MO} = \Psi_{A} + \Psi_{B}$ $IV$. Bond order
| List-$I$ | List-$II$ |
| $A$. $\Psi_{MO} = \Psi_{A} - \Psi_{B}$ | $I$. Dipole moment |
| $B$. $\mu = Q \times r$ | $II$. Bonding molecular orbital |
| $C$. $\frac{N_{b} - N_{a}}{2}$ | $III$. Anti-bonding molecular orbital |
| $D$. $\Psi_{MO} = \Psi_{A} + \Psi_{B}$ | $IV$. Bond order |
Which of the following species absorbs maximum energy in its $HOMO-LUMO$ electronic transition?
Difficult
View SolutionThe increasing order of bond order of $O_2, O_2^+, O_2^-$,and $O_2^{2-}$ is:
Which of the following molecular orbitals has the maximum number of nodal planes?
Medium
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