What is obtained from the Stephen reaction of | vedclass

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(A) The Stephen reaction involves the reduction of alkyl cyanide $(R-C \equiv N)$ using $SnCl_2$ and $HCl$ to form an imine intermediate $(R-CH=NH \cd

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Aldehyde

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(A) The Stephen reaction involves the reduction of alkyl cyanide $(R-C \equiv N)$ using $SnCl_2$ and $HCl$ to form an imine intermediate $(R-CH=NH \cdot HCl)$.Upon hydrolysis with water $(H_2O)$,the imine is converted into an aldehyde $(R-CHO)$ and ammonium chloride $(NH_4Cl)$.The reaction is: $R-C \equiv N + 2[H]$ $\xrightarrow{SnCl_2 + HCl} R-CH=NH \cdot HCl$ $\xrightarrow{H_2O} R-CHO + NH_4Cl$.

What is obtained from the Stephen reaction of alkyl cyanide?

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